# # Enumerate All Users for a Group (including traversing nested groups) # @param distinguishedName - The distinguished name of the object you want to traverse # Brock Moeller # 12/16/2009 # param ( $distinguishedName = "CN=SuperGroup,OU=Groups,DC=serv,DC=ubercorp,DC=com" ) $roles = @{}; $indent = -1; filter EnumMember { $indent += 1; if ($_ -is [System.DirectoryServices.DirectoryEntry]){ $adsiObj = $_; } else { $adsiObj = New-Object System.DirectoryServices.DirectoryEntry("LDAP://" + $_); } if ((-not [String]::IsNullOrEmpty($adsiObj.cn)) -and (-not $roles.ContainsKey($adsiObj.cn))){ $roles[$adsiObj.cn] = 1; $memberOfCount = $adsiObj.member.Count; $("`t"*$indent) + $adsiObj.cn + " [$memberOfCount]"; if (($memberOfCount -gt 0) -and ($indent -lt 900)) { $adsiObj.member | EnumRoles; } } $indent -= 1; } $user = [adsi]"LDAP://$distinguishedName"; $user; $buffer = $user.Path + "`n"; $user | EnumMember | % { $buffer += $_ + "`n" }; "Buffer: " + $buffer.ToString(); [System.IO.File]::WriteAllText("$pwd\$($user.cn).txt", $buffer.ToString());
Sunday, January 31, 2010
Enumeration of All Users in a Group (traversing nested groups) in Active Directory
As a counter part to my previous post, I created a dual of the script which enumerates Groups and their members.
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